Solstice

@solsticen

856 Following

538 Followers

Antonio García Martínez pfp

Antonio García Martínez

It’s sangria time, frens ¡Olé!

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Solstice pfp

🎉 I just minted my DAO BadgeX, and I'm ranking at 0.974! 🎉 Join the fun by claiming yours, and boost your on-chain cred 🚀 👇 https://daobase.ai/point/task?inviteId=RCVB15

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icebreaker pfp

Excited to announce our $5M Seed round led by CoinFund to build the world’s first open professional network. This round helps advance our goal of creating a networking supertool that puts trust, identity, and interoperability directly in the hands of professionals, in web3 and beyond.

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Solstice pfp

hihi! i got my Ⓜ️oxiedrop allocation...did you get yours? cc @betashop.eth @airstack.eth

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Solstice pfp

Hydration is important, but drinking too much water right before bed can disrupt your sleep. Aim to stay hydrated throughout the day to avoid nighttime trips to the bathroom. How do you manage hydration for better sleep?

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From autonomous vehicles to smart cities, AI is reshaping urban living, making transportation safer and more efficient.

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I got my Moxie Pass! Mint yours to be eligible for upcoming airdrops, grants, Fan Tokens and more! cc @betashop.eth @airstack.eth

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@coopahtroopa.eth

The suspense is killing me!

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Believe in yourself and you will be unstoppable.

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Brenner pfp

I don’t understand half the stuff the Pendle team says but that’s a good thing Our customers using our product in ways we hadn’t even imagined is very bullish https://x.com/shadowxyz/status/1803476396959777013?s=46

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Come to Singapore on Sept 22. thenetworkstate.com/conference

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Vitalik Buterin pfp

Vitalik Buterin

The differences between the APIs of numpy, cupy and torch are so fascinating.... ``` >>> import torch as np >>> np.arange(10) tensor([0, 1, 2, 3, 4, 5, 6, 7, 8, 9]) >>> a = np.zeros(20) >>> a[19:-1:-2] = np.arange(10) ``` Torch doesn't let you have ranges that go backwards 🤣 Would love more consistency

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Vitalik Buterin pfp

Vitalik Buterin

https://x.com/AlgebraFact/status/1802110136472817917 This identity simple, but shows important fact: the norm for complex numbers is multiplicative (a+ci)*(b+di) = (ab-cd)+(ad+bc)i norm(x+yi) = sqrt(x^2+y^2) So (ab-cd)^2+(ad+bc)^2 = norm((a+ci)*(b+di)) (a^2+c^2)(b^2+d^2) = norm(a+ci)*norm(b+di) The two are equal

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Vitalik Buterin pfp

Vitalik Buterin

There are 4294967295 hard problems in working with the mersenne31 field: non-pure library functions that look like pure functions, naming things, and off by 4 errors.

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Solstice pfp

Where light and shadow embrace, marking the rhythm of my journey.

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Zach pfp

babe wake up new slack sounds dropped

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Weaving tales with words of magic, enchanting hearts with lyrical grace.

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