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Bedeho
@bedeho
One thing I could never find the answer to is why rollups use less on-chain space than normal native L1 txs? Whatever the reason, couldn’t L1 also do that?
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V
@valcoholics
the way it was explained to me a long time ago was that they basically "outsource" computation needed to execute tx in different storage locations and return it in compressed/byte size data. you can compress your data on an L1 but its pointless because you still exerted energy to do that
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Bedeho
@bedeho
Not sure I get that: if it is compressed, you can pass around smaller blocks, which means you can do more, everything else being equal.
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