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新手来了，必回关
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Vitalik Buterin
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https://x.com/AlgebraFact/status/1802110136472817917 This identity simple, but shows important fact: the norm for complex numbers is multiplicative (a+ci)*(b+di) = (ab-cd)+(ad+bc)i norm(x+yi) = sqrt(x^2+y^2) So (ab-cd)^2+(ad+bc)^2 = norm((a+ci)*(b+di)) (a^2+c^2)(b^2+d^2) = norm(a+ci)*norm(b+di) The two are equal
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syy
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一起来关关
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syy
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关关走起🤝 🤝 🤝
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syy
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大家好，互关走起
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新手上路，关注走起
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