Stephanie

@stephanieu

846 Following

314 Followers

Stephanie pfp

🎉 I just minted my DAO BadgeX, and I'm ranking at 0.974! 🎉 Join the fun by claiming yours, and boost your on-chain cred 🚀 👇 https://daobase.ai/point/task?inviteId=NWBZFG

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hihi! i got my Ⓜ️oxiedrop allocation...did you get yours? cc @betashop.eth @airstack.eth

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Stephanie pfp

Host an origami workshop at home or virtually. Provide materials and tutorials for various designs. This intricate art form promotes focus and patience, allowing participants to create beautiful paper sculptures while enjoying a relaxing, hands-on activity.

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Sunlight dances through the lavender fields, painting the air with soothing hues.😀

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I got my Moxie Pass! Mint yours to be eligible for upcoming airdrops, grants, Fan Tokens and more! cc @betashop.eth @airstack.eth

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Be stronger than your excuses.

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Hi, I'm Stephanie. I'm a nutritionist and fitness coach who loves outdoor photography.

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Vitalik Buterin pfp

Vitalik Buterin

There are 4294967295 hard problems in working with the mersenne31 field: non-pure library functions that look like pure functions, naming things, and off by 4 errors.

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Calling for Designers - thepunkmonk.eth What I would like to do is find some designers who want to take the concepts in this collection and help me build brand assets, starting with a simple black t-shirt, with a white only screen print. The front should only have the brand on the pocket, and the back is fair game. I do like solid block art like old style surf images, but whatever you like. The brush style is Japanese gyosho calligraphy. If you want to participate and submit your images in a Zora collection, I will mint the ones I appreciate, and reward the top 3 winners. I will make limited runs of the t-shirts. Alert me at fc:horneps https://zora.co/collect/zora:0xdb2575d377bc2c76b333e87ed634d4f300cc298c

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pugson pfp

bulgogi bibimbap

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Vitalik Buterin pfp

Vitalik Buterin

https://x.com/AlgebraFact/status/1802110136472817917 This identity simple, but shows important fact: the norm for complex numbers is multiplicative (a+ci)*(b+di) = (ab-cd)+(ad+bc)i norm(x+yi) = sqrt(x^2+y^2) So (ab-cd)^2+(ad+bc)^2 = norm((a+ci)*(b+di)) (a^2+c^2)(b^2+d^2) = norm(a+ci)*norm(b+di) The two are equal

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mike rainbow (rainbow mike) ↑ pfp

mike rainbow (rainbow mike) ↑

@mikedemarais.eth

worthless fiat uniswap socks

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