Don

@southldnft

127 Following

24 Followers

Don pfp

0 reply

0 recast

0 reaction

Layer3 pfp

Discover leading dapps on @arbitrum's L2 ecosystem: @traderjoe, @uniswap, @opensea, @treasuredao, @jumperexchange, @pendle-fi, @beefy, and more! Compete for 32,000 ARB as incentives in the Arbitrum Hub today. ⛓️ → https://app.layer3.xyz/collections/arbitrum-hub

24 replies

57 recasts

236 reactions

Don pfp

0 reply

0 recast

1 reaction

Don pfp

0 reply

0 recast

1 reaction

Lauren McDonagh-Pereira pfp

Lauren McDonagh-Pereira

@lampphotography

My CasterRank is #15 🎩✨⚡🍖🎭🃏

25 replies

4 recasts

28 reactions

Don pfp

0 reply

0 recast

1 reaction

Layer3 pfp

Mint "@thedoodles moves to @base ft. Jullian Holguin & @jessepollak." Claim 150 DEGEN in rewards for collecting the latest Mint Podcast. https://app.layer3.xyz/quests/mint-podcast-doodles-move-to-base

26 replies

42 recasts

219 reactions

Don pfp

0 reply

0 recast

0 reaction

Emre Ekinci pfp

Just checked my Warpcast profile stat using @warpdrive Check the Frame below to get stat for your profile as well

6 replies

9 recasts

28 reactions

Don pfp

Will try to implement

0 reply

0 recast

0 reaction

hellno the optimist pfp

hellno the optimist

Fastest Path to the Farcaster Power Badge: 10 Proven Strategies @biji went deep with this one and prepared a straightforward playbook for you https://paragraph.xyz/@herocast/the-farcaster-power-badge-bible

14 replies

11 recasts

47 reactions

Don pfp

0 reply

0 recast

1 reaction

Don pfp

Wow that looks good

0 reply

0 recast

0 reaction

Todd Goldberg pfp

A double espresso is the perfect way to drink coffee: * Tastes great * ~0 calories (Fast friendly) * Good amount of caffeine * Fast and efficient * Pairs well with sparkling water

57 replies

14 recasts

171 reactions

ciniz 🐹 pfp

how would you describe farcaster to someone who primarily uses instagram or tiktok without saying it's like twitter

152 replies

14 recasts

162 reactions

Vitalik Buterin pfp

Vitalik Buterin

https://x.com/AlgebraFact/status/1802110136472817917 This identity simple, but shows important fact: the norm for complex numbers is multiplicative (a+ci)*(b+di) = (ab-cd)+(ad+bc)i norm(x+yi) = sqrt(x^2+y^2) So (ab-cd)^2+(ad+bc)^2 = norm((a+ci)*(b+di)) (a^2+c^2)(b^2+d^2) = norm(a+ci)*norm(b+di) The two are equal

137 replies

266 recasts

1174 reactions

Don pfp

0 reply

0 recast

0 reaction

Arrotu pfp

Have a based morning

40 replies

8 recasts

43 reactions

Don pfp

That's amazing I committed all of mine which was only 9k.. but I hope it helps

0 reply

0 recast

0 reaction

@developer pfp

Looks like the BUILD Summer Fund passed the 50% target 👏

42 replies

8 recasts

48 reactions