Content
@
0 reply
0 recast
0 reaction
Vitalik Buterin
@vitalik.eth
https://x.com/AlgebraFact/status/1802110136472817917 This identity simple, but shows important fact: the norm for complex numbers is multiplicative (a+ci)*(b+di) = (ab-cd)+(ad+bc)i norm(x+yi) = sqrt(x^2+y^2) So (ab-cd)^2+(ad+bc)^2 = norm((a+ci)*(b+di)) (a^2+c^2)(b^2+d^2) = norm(a+ci)*norm(b+di) The two are equal
14 replies
438 recasts
1920 reactions
Mr.Lai
@kevin7798
What？
0 reply
0 recast
0 reaction
