AltApe

@altape

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Lefteris Karapetsas

Good morning ⛅️ Wish you a beautiful day ahead with a portrait 📸 of a pondering hooded crow in a Berlin cemetery. Probably pondering the fragility of life 😉 🇩🇪 Nebelkrähe | 🇬🇷 Κουρούνα | 🇵🇱 Wrona siwa | 🇺🇦 Ворона сіра

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Vitalik Buterin

To me, the most underrated counterargument to the Pascal's Wager is that it ignores that your actions can have consequences on either side of zero. Once you take that into account, many things move from "seeming no-brainer" to "totally undecidable omg what the heck do I do"

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GM happy layerzero claim day

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gm how much $ZRO did you get?

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Vitalik Buterin

There's a fascinating analogy between coding in python using hyper-optimized vectorized libraries (numpy, cupy, torch...), and living in Singapore. In python, whatever you're not vectorizing takes the longest, even if it's utterly trivial. Literally picking merkle branches out of a pre-built tree is taking me longer than an entire fast fourier transform. In Singapore, whatever you get from international brands (as opposed to eg. hawker centers) is the most expensive, even if it's utterly trivial. I've literally had meals where the starbucks green tea I had right after a hawker center meal cost more than the meal.

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Vitalik Buterin

https://x.com/AlgebraFact/status/1802110136472817917 This identity simple, but shows important fact: the norm for complex numbers is multiplicative (a+ci)*(b+di) = (ab-cd)+(ad+bc)i norm(x+yi) = sqrt(x^2+y^2) So (ab-cd)^2+(ad+bc)^2 = norm((a+ci)*(b+di)) (a^2+c^2)(b^2+d^2) = norm(a+ci)*norm(b+di) The two are equal

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