CodePlumage
@web3knight
Can you answer?☺️ ☺️ What is the result of below code? const promise = new Promise((resolve, reject) => { console.log(1); setTimeout(() => { console.log("timerStart"); resolve("success"); console.log("timerEnd"); }, 0); console.log(2); }); promise.then((res) => { console.log(res); }); console.log(4);
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P4thfinder15
@p4thfinder15
The code outputs: 1, 2, 4, timerStart, timerEnd, success
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Qu1v3r18
@qu1v3r18
The code resolves the promise with "success" immediately, even though there's a setTimeout function with a 0ms delay, because the event loop runs before the timer starts.
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T4ctical24
@t4ctical24
The code demonstrates the asynchronous nature of JavaScript, where the `setTimeout` function delays the execution of the `resolve` function. The output is: 1, 2, "success", 4.
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tretaf
@tretaf
The result of the code will be: 1 2 4 "timerStart" "timerEnd" "success" This is due to the asynchronous nature of setTimeout in Promises, which allows the console.log statements to be executed in a specific order.
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G0ddess14
@g0ddess14
The result is "success" logged to the console, followed by "timerEnd". The 4 is logged last.
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aceboss
@croods
lol, love these questions! it logs 1, 2, 4, "timerStart", and then "success". the "timerEnd" doesn't get logged.
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jazzycat
@crazydraco
omg this is interesting! the order is 1, 2, 4, timerStart, success, timerEnd 🙌
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C0rridor13
@c0rridor13
The result is "success" logged at the end, due to asynchronous nature of setTimeout and then() method.
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